SSC-JE’21 CE: Daily Practices Quiz. 17-July-2021

Quiz: Civil Engineering
Exam: SSC-JE
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. In a slab, the minimum reinforcement using steel of grade Fe 415 is –
(a) 0.12% of its gross sectional area
(b) 0.20% of its gross sectional area
(c) 0.15% of its gross sectional area
(d) 0.10% of its gross sectional area

Q2. When the degree of consolidation is 50% about how much is the time factor?
(a) 0.5
(b) 2.0
(c) 1.0
(d) 0.2

Q3. A simply supported beam of span length L carries a uniformly distributed load of 2.0 kN/m and has a diameter of 75 mm. The maximum value of bending moment produced is 8.5 kN-m. What is the value of span length (m) of the beam?
(a) 5.8
(b) 34
(c) 7
(d) 2

Q4. The most commonly used base for iron and steel work is
(a) Zinc white
(b) White lead
(c) Red lead
(d) None of the above

Q5. The design value of stopping sight distance for a two-lane, two-way traffic would be; –
(a) Half the stopping sight distance
(b) Equal to stopping sight distance
(c) Twice the stopping sight distance
(d) Three times the stopping sight distance

Q6. The volume (in m³) of coarse aggregate required to make 100m³ of 1:2:4 concrete is ………….
(a) 84
(b) 87
(c) 92
(d) 96

Solutions

S1. Ans.(a)
Sol. Minimum reinforcement.
For Mild steel bar → 0.15% of gross area
For HYSD bar → 0.12% of gross area

S2. Ans.(d)
Sol. When %U < 60%
Time factor (T_v )=π/4 (%U)^2
T_V=3.14/4 (0.50)^2
▭(T_v=0.19625)
▭(T_v≈0.2)

S3. Ans.(a)
Sol. Maximum bending moment for simply supported in case of UDL.
(WL^2)/8=8.5 KN-m
L=√((8.5×10^3×8)/(2×10^3 ))
L = 5.83 m

S4. Ans.(c)
Sol. Red lead is used as base for painting of iron and steel work as it reduces the problem of corrosion.

S5. Ans.(b)
Sol. As per IRC, the design value of stopping right distance (SSD) –
(a) For single lane one way = SSD
(b) For single lane two way = 2SSD
(c) For two lane two way = SSD

S6. Ans.(b)
Sol. The volume of dry concrete is 1.52 times of quantity of wet concrete.
Quantity of coarse aggregate for 100m³ of wet concrete = 100 × 1.52 = 152 m³
Quantity of coarse aggregate in 1:2:4 Proportion of cement concrete = 4/7×152 = 86.85 ≃ 87 m³.

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