SSC-JE’21 CE: Daily Practices Quiz. 16-July-2021

Quiz: Civil Engineering
Exam: SSC-JE
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. The true length of line is known to be 300m. when this line is again measured with a new 30 m tape, the length is found to be 300.90 m. the correct length of the tape is
(a) 28.90 m
(b) 29.91 m
(c) 30.19 m
(d) 28.30 m

Q2. Find the plinth area of building if a building built up area 350m² is constructed with a courtyard of 5.5 × 6.5m inside the building
(a) 314.24 m²
(b) 314.25 m²
(c) 314.26 m²
(d) 314.27 m²

Q3. The defects of a tree caused by injuries sustained during its young age are called _________.
(a) burls
(b) knots
(c) shakes
(d) upsets

Q4. A mean annual runoff 2m³/s from a catchment of area 10 km² represents an effective rainfall of nearly:
(a) 530 cm
(b) 590 cm
(c) 630 cm
(d) 658 cm

Q5. A material has identical properties in all directions is said to be
(a) Homogeneous
(b) Isotropic
(c) Anisotropic
(d) Orthotropic

Q6. Partial safety factors for concrete and steel respectively may be taken as:
(a) 1.5 and 1.15
(b) 1.5 and 1.78
(c) 3 and 1.78
(d) 3 and 1.2

Solutions

S1. Ans.(b)
Sol. True length of line (L) = 300 m
Measured length of line (L’) = 300.90 m
Length of tape (l) = 30 m.
True length of tape (l’) =?
L × l = L’ × l’
300 × 30 = 300.9 × l’
l^’=(300×30)/300.9
▭(l^’=29.91m)

S2. Ans.(b)
Sol. Built up area = 350 m²
Courtyard area = 5.5 × 6.5 m² = 35.75 m²
Plinth area = 350 – 35.75 = 314.25 m²

S3. Ans.(a)
Sol. Burls → these are the uneven projections on the body of the tree during its growth. These are mainly due to effects of injuries and shocks during its young age.

S4. Ans.(c)
Sol. Given,
Annual runoff = 2 m³/s
Area of = 10 km² = 10 × 10^6 m²
Effective rainfall = (Annual Runoff)/(Area of catchment)
=(2×60×60×24×365〖 m〗^3 )/(10×10^6 m^2 )
=6.3072 m.
=630.7 cm.

S5. Ans.(b)
Sol. Isotropic → A material is said to be isotropic when it has same properties in all direction.
Anisotropic → A material is said to be anisotropic when it has different properties in all direction.
Homogenous → Same property at each cross-section.
Orthotropic → Different property in three mutually perpendicular direction.

S6. Ans.(a)
Sol. In limit state method.
Partial safety factor for RCC = 1.5
Partial safety factor for steel = 1.15
In working state method.
Partial safety factor for R.C.C. = 3
Partial safety factor for steel = 1.78

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