**Quiz: Civil Engineering **

**Exam: UPPSC-AE**

**Topic: Miscellaneous**

**Each question carries 1 mark**

**Negative marking: 1/3 mark**

**Time: 10 Minutes**

Q1. If the fore bearing of the line AB is 119°48’ then back baring is:

(a) 299° 48’

(b) 209°48’

(c) 119°48’

(d) 319°48’

Q2. Calculate detention time of the tank whose breadth is 2 m, length is 4 m and depth is 2.5m. the rate of flow is 4 x 10³ liters per hour

(a) 5 hours

(b) 4 hours

(c) 5.5 hours

(d) 2.5 hours

Q3. If nominal shear stress (τ_v) exceeds the design shear strength of concrete (τ_C), the shear reinforcement as per IS – 456 will be provided for shear equal to –

(a) τ_C

(b) τ_v

(c) τ_v- τ_C

(d) τ_v+ τ_C

Q4. A soil has a discharge velocity of 6 × 10^(-7) m/s and void ratio of 0.5. What is its seepage velocity?

(a) 3 × 10^(-7) m/s

(b) 6 × 10^(-7) m/s

(c) 12 × 10^(-7) m/s

(d) 18 × 10^(-7) m/s

Q5. The hydraulic head that would produce a quick sand condition in a sand stratum of thickness 1.8m, specific gravity 2.65 and void ratio 0.65 is equal to:

(a) 1.0 meter

(b) 1.2 meter

(c) 1.6 meter

(d) 1.8 meter

Q6. What will be the shift of the transition curve, if the length of transition curve is 80 m and radius of the curve is 320 m?

0.011

0.83

0.89

21.33

Q7. Lacey’s silt factor for medium silt whose average gain size is 0.25 mm, is likely to be:

(a) 0.66

(b) 0.77

(c) 0.88

(d) 0.99

Q8. The operation of converting limestone into quicklime by heating it to temperature upto 900°C and releasing carbon dioxide is known as:

(a) Charging

(b) Calcination

(c) Drawing

(d) Hydrating

Q9. The maximum dimension of a core section for a rectangular cross-section under eccentric loading on a column (b×d) is

(a) b/6

(b) d/6

(c) d/8

(d) b/3 and d/3

Q10. Newton’s law of viscosity is a relationship between-

(a) Rate of shear strain & temperature

(b) Shear stress & rate of shear strain

(c) Pressure, velocity & temperature

(d) Shear stress & velocity

Solutions

S1. Ans.(a)

Sol. fore bearing of line ‘AB’ = 119°48’

Fore baring is less than 180° so we calculate back bearing by adding 180°. If fore bearing greater than 180° than we subtract 180° from it.

Back bearing of line AB = 180°+〖119°48〗^’=〖299°48〗^’

S2. Ans.(a)

Sol. Given,

Length (L) = 4m.

Breadth (B) = 2 m.

Depth (D) = 2.5 m.

Discharge (Q) = 4 × 10³ l/hour

Detention time of tank (t_d) =?

t_d = (Volume of tank (V))/(Discharge (Q) )

= (4×2×2.5 (m^3 ))/(4×10^3×10^(-3) (m^3 \/hour) )

= 5 hours.

S3. Ans.(c)

Sol. if nominal shear stress (τ_v ) exceceds the design shear strength of concrete (τ_c ) than shear reinforcement will be provided to resist (τ_v-τ_c )

Some important point in shear reinforcement

→ if τ_V> τ_cmax then redesign the section

→if τ_V<τ_c/2 then no shear reinforcement provided

→ if τ_V < τ_c minimum shear reinforcement provided

→ if τ_V > τ_c then design shear reinforcement to resist (τ_V-τ_c )

S4. Ans.(d)

Sol. discharge velocity (V) = 6 × 10^(-7) m/s

Void ratio (e) = 0.5

Porosity (n) = e/(1+e)

= 0.5/(1+0.5)

= 0.5/1.5

=0.33

Seepage velocity (V_s ) = V/n

=(6×10^(-7))/0.33

V_s=18.18× 10^(-7) m/sec

S5. Ans.(d)

Sol. thickness (t) = 1.8 m

G = 2.65

Void ratio (e) = 0.65

For quick sand condition –

Critical hydraulic gradient (i_c ) = (G-1)/(1+e)

(G-1)/(1+e)=∆h/t

(2.65-1)/(1+0.65)=∆h/1.8

1.65/1.65=∆h/1.8

▭(∆h=1.8 meter)

S6. Ans.(b)

Sol. Given, length of transition curve (L) = 80 m.

Radius of the curve (R) = 320 m.

Shift (S) = L^2/24R = (〖(80)〗^2 )/(24×320) = 0.83 m.

S7. Ans.(c)

Sol. Given, dmm = 0.25 mm

Lacey’s silt factor (f) = 1.76 √dmm

= 1.76 √0.25

= 0.88

S8. Ans.(b)

Sol. Calcination is a process of heating the limestone up to redness.

CaCO_3 ——Calcination——- CaO+CO_2

S9. Ans.(d)

Sol. The maximum dimension of a core section for a rectangular cross-section under eccentric loading on a column (b × d) is b/3 or d/3. The shape of kern or core for rectangular and I – section is Rhombus.

S10. Ans.(b)

Sol. Newton’s law states that the shear stress is directly proportional to the rate of shear strain for Newtonian fluid.

τ α dv/dy

▭(τ=μ.dv/dy)