Quiz: Civil Engineering
Each question carries 1 mark
Negative marking: 1/4 mark
Time: 10 Minutes
Q1. Francis turbine is a:
(a) Axial flow turbine
(b) Radial flow turbine
(c) impulse turbine
(d) Outward flow turbine
Q2. In reaction turbine-
(a) flow can be regulated without loss
(b) water may be allowed to enter apart of whole of wheel circumference
(c) the outlet must be above the tail race
(d) there is only partial conversion of available head to velocity head before entry to runner
Q3. Kaplan turbine-
(a) has poor part-load efficiency
(b) is used where high head is available
(c) has inlet adjusted guided vanes
(d) has adjustable runner blades
Q4. Weber number is the ratio of inertial force to
(a) gravitational force
(b) surface tension
Q5. A Pelton wheel is:
(a) Radial flow impulse turbine
(b) Inward flow impulse turbine
(c) Axial flow impulse turbine
(d) Outward flow impulse turbine
Q6. Maximum theoretical efficiency of Pelton wheel is obtained when the ratio of bucket speed to jet speed is:
Q7. If E_c and E_s are modulus of elasticity of concrete and steel respectively, then the modular ratio (m) will be
(c) (E_c+E_s)/(E_s-E_c )
Q8.Partial safety factors for concrete and steel respectively may be taken as:
(a) 1.5 and 1.15
(b) 1.5 and 1.78
(c) 3 and 1.78
(d) 3 and 1.2
Q9. The ratio of the maximum diameter of the reinforcing bar in a slab and the total thickness of the slab should not exceed …………….
Q10. A sand deposit has a porosity of 1/3 and its specific gravity is 2.5. The critical hydraulic gradient to cause sand boiling in the stratum will be
Sol. Francis turbine is inward flow radial reaction turbine.
Sol. in a reaction turbine, there is only partial conversion of available heat to velocity head before entry to runner. Thus at entrance to reaction turbine the fluid will have both pressure energy as well as kinetic energy.
Sol. Kaplan turbine has adjustable runner blade due to that it has high part load efficiency.
Sol. Weber number is the ratio of intertie force to surface tension.
Sol. Pelton wheel is the turbine comes in category of inward flow impulse turbine.
Sol. maximum actual efficiency.
V = 2u
u = 0.5 V
Theoretically maximum efficiency.
Sol. ▭(Modular Ratio (m)=(Modulas of elasticity of steel(E_s ))/(Modulus of plasticity of concrete(E_c ) ))
E_c=5000 √fck (Acc. To IS 456:2000)
Sol. In limit state method.
Partial safety factor for RCC = 1.5
Partial safety factor for steel = 1.15
In working state method.
Partial safety factor for R.C.C. = 3
Partial safety factor for steel = 1.78
Sol. ▭(maximum diameter of reinforcement in slab ≯1/8× thickness of slab)
Sol. porosity (n) = 1/3
G = 2.5
Critical hydraulic gradient (ic) = ?
e = n/(1-n )=(1\/3)/(2\/3)=0.5